TSUBAKI Power Transmission Products Information Site 　Technical Data 　Large size conveyor chain 　Selection 　Selection example

n = 50000 250 × 2 + 12 × 2 = 412 × 2 = 824 links

No. of rollers = Length of material Chain pitch = 1000 250 = four

However, as there is an uneven load only four rollers will receive the load.

Roller load = 2000 × g 1000 × 1 4 = 4.9kN {500kgf}/each

From Table 11, we can select the following Bearing Roller Conveyor Chain: RF12250BF-1LA2, allowable load 5.49kN{560kgf} or the following RF Conveyor Chain: RF26250F-DT-1LA2, allowable load 5.30kN{540kgf}.

Due to simplified selection, load of conveyor weight and starting impact will not considered in the following procedure. 2000kg × 40pcs/2 strands = 40,000kg/strand

From the table on the right, RF10 ton size Bearing Roller Conveyor Chain (53300kg) and RF17 ton size RF Conveyor Chain (44600kg) can be selected.

When comparing roller allowable load and allowable loading mass, roller allowable load should be the first consideration in selection.

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Typical value that will not cause roller rotational failure or premature wear, assuming use under lubricated conditions. When selecting, include an extra margin of safety over allowable values according to operating conditions (high speeds, heavy loads, long-term operation) and expected life.

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Typical value that will not cause roller rotational failure or premature wear, assuming use under lubricated conditions. When selecting, include an extra margin of safety over allowable values according to operating conditions (high speeds, heavy loads, long-term operation) and expected life.

Bearing roller conveyor chain (f1 = 0.03 )

T = 2000kg × g 1000 × 40 × 0.03 = 23.5kN{2400kgf}

Conveyor chain (f = 0.08 )

T = 2000kg × g 1000 × 40 × 0.08 = 62.8kN{6400kgf}

Bearing roller conveyor chain

Conveyor chain

Motor kW = T × V 60 × 1.1 × 1 η = (η= 0.85)

Bearing Roller Conveyor Chain Required Power

kW = 23.5 × 10 60 × 1.1 × 1 0.85 = 5.1kW

Conveyor Chain Required Power

kW = 62.8 × 10 60 × 1.1 × 1 0.85 = 13.5kW

Simplified Allowable Loading Mass Chart

Unit: kg/per strand
Chain Size	Conveyor chain (DT)	Bearing roller conveyor chain (DT)
RF03	5400	14000
RF05	12500	33300
RF08・450	14300	36700
RF10	20500	53300
RF12	33900	90000
RF17	44600	116700
RF26	57100	150000
RF36	86600	230000
RF60	91100	-
RF90	143800	-
RF120	201800	-

Note) Coefficient of friction on horizontal conveyor [Conveyor chain ：0.08/Bearing roller ：0.03]

n = 30000 100 × 2 + 12 × 2 = 612 × 2 = 1224 links

30 cardboard boxes will be carried on the conveyor. Thus, conveyor total loading mass is 100×30 = 3000kg, and the coefficient of friction under lubricated conditions from Table 5 is 0.08.

Required power T₁ to convey the cardboard boxes only is
T₁ = 3000 × g 1000 × 0.08 = 2.35kN {T₁ = 3000 × 0.08 = 240kgf}

Next, with each slat having a mass of 10kg, pitch at 100, Slat Mass = 10 × 1000 100 = 100kg/m

Required power T₂ to convey slats only
T₂ = 2.1 × 100 × 30 × g 1000 × 0.08 = 4.94kN {T₂ = 2.1 × 100 × 30 × 0.08 = 504kgf}
T₁ + T₂ = 2.35 + 4.94 = 7.29kN {T₁ + T₂ = 240 + 504 = 744kgf}

Maximum allowable load of RF03100F-DT (2 strands) is 4.20kN × 2 strands = 8.40kN{860kgf} and so can be used

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Limit value that takes fatigue fracture and wear into consideration, assuming use under lubricated conditions. By determining a corrected chain tension based on a selection described in our catalog and using the chain below this value, no anomalies will occur early in operation. However, this does not apply when performance has deteriorated due to use under extreme environmental conditions.

With RF03100F-DT-1LA2, the required power T₃to move the chain only is

T_MAX = T₁ + T₂ + T₃ = 2.35 + 4.94 + 0.30 = 7.59kN

{T_MAX = T₁ + T₂ + T₃ = 240 + 504 + 30.2 = 774kgf}

Assuming the load acting on both strands is the same, then corrected chain load T’MAX for one strand T'_MAX

T'_MAX = 7.59/2 × K_v × K_T × K_s = 7.59/2 × 1.0 × 1.0 × 1.0 = 3.80kN

Maximum allowable load for one strand of RF03100F-1LA2 is 4.20kN, so T’_MAX=3.80kN<4.20kN

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Limit value that takes fatigue fracture and wear into consideration, assuming use under lubricated conditions. By determining a corrected chain tension based on a selection described in our catalog and using the chain below this value, no anomalies will occur early in operation. However, this does not apply when performance has deteriorated due to use under extreme environmental conditions.

Both roller allowable load and attachment allowable load satisfy the values in Tables 10 and 11.

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Typical value that will not cause roller rotational failure or premature wear, assuming use under lubricated conditions. When selecting, include an extra margin of safety over allowable values according to operating conditions (high speeds, heavy loads, long-term operation) and expected life.

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Vertical load that an “A” attachment can accept. When using “K” attachments, calculate this value by doubling the allowable load of the corresponding A attachment. Depending on the shape and structure of attachments to be installed by the customer, force may be generated that will cause A attachments to twist. Contact a Tsubaki representative if you have any concerns.

The pitch circle diameter of a sprocket with pitch=100, N = 12T is Φ386.4

Tr = 7.59 × 386.4 × 1 2 × 1 1000 = 1.47kN・m

{Tr = 774 × 386.4 × 1 2 × 1 1000 = 149.5kgf・m}

kW = 7.59×15 60 × 1.1 × 1 0.85 = 2.46kW

{kW = 774 × 15 102 × 60 × 1.1 × 1 0.85 = 2.46kW}

n = 30000 250 × 2 + 12 × 2 = 252 × 2 = 504 links

T₁ = 16.7 × 90 28 × (30 + 1) × g 1000 = 16.3kN

{T₁ = 16.7 × 90 28 × (30 + 1) = 1664kgf}

　　part: 1 m is added to sprocket center distance to account for shock load when loading (Calculate chain load: Refer to vertical conveyor )

With a chain pitch of 250 and buckets attached every two links, bucket mass is 25kg×2=50kg/m.

T₂= 50 × g 1000 × (30 + 1) = 15.2kN

{T₂= 50 × (30 + 1) = 1550kgf}

{T₁ + T₂ = 1664 + 1550 = 3214kgf}

We tentatively select B17250S (maximum allowable load: 35kN) as a chain that can satisfy the maximum allowable load requirements with two strands.

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Limit value that takes fatigue fracture and wear into consideration, assuming use under lubricated conditions. By determining a corrected chain tension based on a selection described in our catalog and using the chain below this value, no anomalies will occur early in operation. However, this does not apply when performance has deteriorated due to use under extreme environmental conditions.

The mass of B17250S with a GA4 attachment every two links is 15kg/m.

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T₃ = 15 × 2 × (30 + 1) × g 1000 = 9.12kN

{T₃ = 15 × 2 × (30 + 1) = 930kgf}

16.3 × 0.6 + 15.2 2 + 9.12 2 = 21.9kN

{1664 × 0.6 + 1550 2 + 930 2 = 2238kgf}

We include a 1.5 leeway in light of wear life in unlubricated conditions.
Design chain tension T'_MAX = 21.9 × Kv × KT × Ks × 1.5 = 21.9 × 1.05 × 1.0 × 1.0 × 1.5 = 34.5kN

{T'_MAX = 2238 × 1.05 × 1.0 × 1.0 × 1.5 = 3524kgf}

From the above, B17250S-CT-2LGA4 can be used.

Note) The offset load between two strands of chain differs depending on conveyance conditions. Use a value that corresponds to actual usage conditions.

Tr = 18.1 × 965.9 × 1 2 × 1 1000 = 8.74kN・m

{Tr = 1849 × 965.9 × 1 2 × 1 1000 = 893kgf・m}

kW = 18.1 × 28 60 × 1.1 × 1 0.85 = 10.9kW

{kW = 1849 × 28 102 × 60 × 1.1 × 1 0.85 = 10.9kW}

TSUBAKI Power Transmission Products Information Site

Technical Data Large size conveyor chain Selection

10. Selection example

10.1 Bearing roller conveyor chain

1) No. of links

2) Confirm roller load

3) Check allowable loading mass on conveyor

4) Select motor size (Assume 10% dynamic loss )

Simplified Allowable Loading Mass Chart

10.2 Conveyor Type ：Horizontal Slat Conveyor (Horizontal )

1) No. of links ：n

2) Chain size

3) Drive sprocket torque ：Tr

4) Power required

10.3 Conveyor Type ：Continuous Bucket Elevator (Vertical )

1) No. of links ：n

2) Chain size

3) Drive sprocket torque ：Tr

4) Power required ：Tr